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X^2+1000X+1000=0
a = 1; b = 1000; c = +1000;
Δ = b2-4ac
Δ = 10002-4·1·1000
Δ = 996000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{996000}=\sqrt{400*2490}=\sqrt{400}*\sqrt{2490}=20\sqrt{2490}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1000)-20\sqrt{2490}}{2*1}=\frac{-1000-20\sqrt{2490}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1000)+20\sqrt{2490}}{2*1}=\frac{-1000+20\sqrt{2490}}{2} $
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